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How do I wire a generator warning light?
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fordpop



Joined: 23 Aug 2011
Posts: 18
Location: Devon

PostPosted: Wed Feb 15, 2012 9:34 pm    Post subject: How do I wire a generator warning light? Reply with quote

I am fitting a fuse box and doing some rewiring on my 1926 Austin 12. Although the car is fitted with an ammeter, I thought I would also fit a generator warning light on the dashboard. This should hopefully come on when the ignition is switched on and go out when (if...?) the generator begins to charge.

The car has been fitted with a Lucas voltage control box and this has a warning light terminal - so ok, there is one connection to the lamp. My question is, where does the other side of the warning lamp go?

I am assuming it must take a live feed from the ignition switch but I can't quite get my head around this set up.

Anyone care to confirm / explain please?

Thanks,
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Alan

1957 Ford 103E Popular
1926 Austin 12/4 Clifton Tourer
1966 Humber Sceptre MkII
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47Jag



Joined: 26 Jun 2008
Posts: 782
Location: Bothwell, Scotland

PostPosted: Wed Feb 15, 2012 9:38 pm    Post subject: Reply with quote

Alan,

Wire one side of you warning light to the ignition switch and the other to the 'D' terminal of the regulator.

Art
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fordpop



Joined: 23 Aug 2011
Posts: 18
Location: Devon

PostPosted: Wed Feb 15, 2012 10:11 pm    Post subject: Reply with quote

Cheers Art
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Alan

1957 Ford 103E Popular
1926 Austin 12/4 Clifton Tourer
1966 Humber Sceptre MkII
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Jim.Walker



Joined: 27 Dec 2008
Posts: 1234
Location: Chesterfield

PostPosted: Wed Feb 15, 2012 11:34 pm    Post subject: Reply with quote

47Jag wrote:
Alan,

Wire one side of you warning light to the ignition switch and the other to the 'D' terminal of the regulator.

Art


Surely that should be the F terminal? Otherwise it will glow with reverse voltage when the dynamo charges.
Jim.
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Quote from my late Dad:- You only need a woman and a car and you have all the problems you
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47Jag



Joined: 26 Jun 2008
Posts: 782
Location: Bothwell, Scotland

PostPosted: Wed Feb 15, 2012 11:40 pm    Post subject: Reply with quote

No! The lamp is lit by the potential differences (voltage) between the battery and the dynamo (D terminal). The cut-out closes and both sides of the lamps are then at the same voltage and it's out.

Art
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